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another question guys! :)

Discussion in 'DAT Discussions' started by JustwantDDS, Aug 10, 2011.

  1. JustwantDDS

    JustwantDDS DrAMG
    7+ Year Member

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  2. DentistDMD

    Removed

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    K for the first reaction = (NO2)^2 / [(NO)^2 * O2] = 2
    K for the second reaction = [O2]^(1/2) * NO / NO2
    Take the square root of both sides for the first equation and you get:
    NO2/[NO * (O2)^1/2] = 2^(1/2)
    Take the reciprocal of both sides and you get K for the second reaction which would be 1/[2^(1/2)]
    Since 1 is equivalent to 1^(1/2), 1/[2^(1/2)] = (1/2.0)^(1/2).
    Therefore, the answer is A.
     
  3. rah08e

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    This is easy. Destroyer has a problem just like this.


    The new reaction has been flipped, so put 1 over your K value (K=2.0) --> 1/2.0

    Then, since you cut the # of moles in half, you square root it (aka to the 1/2 power) --- > (1/2.0)^1/2

    If the # of moles doubled, you would have squared your 1/2.0 instead of square rooting it.
     

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