Another tough chem calculation question

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Smooth Operater

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How many grams of Al2(SO4)3 are needed to make
87.5 g of 0.3 m Al2(SO4)3 solution? (Atomic weights of
Al = 27, S = 32, O = 16)

A. 102.6/(87.5 x 1000)
B. (87.5 x 102.6)/1000
C. 87.5/1102.6
D. 102.6/(87.5 x 1102.6)
E. (87.5 x 102.6)/1102.6

Kaplan has its own solution, and I am wondering is there any other way to approach this question. If you know how to do this Q, plz explain. Thanks!

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