arrange the following (chem)

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pistolpete007

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arrange the following in bond length
then in bond order (increasing order)

A.N-F
B.N-Cl
C. N-Br

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I think you should look at atom size for this one.. bigger atom = longer bond length. So N-Br > N-Cl > N-F
 
Bond length: NF<NCl<NBr

bond order would all be the same, they are all single bonds....

Bond energy: NF>NCl>NBr

The more electronegative the more its held closer so the bond length would decrease as you have a more electronegative ion, and bond energy (the energy to break the bond) would increase for more electronegative ions because it is held tighter...the Flourine doesnt want to let go of Nitrogen....
 
Bond length: NF<NCl<NBr

bond order would all be the same, they are all single bonds....

Bond energy: NF>NCl>NBr

The more electronegative the more its held closer so the bond length would decrease as you have a more electronegative ion, and bond energy (the energy to break the bond) would increase for more electronegative ions because it is held tighter...the Flourine doesnt want to let go of Nitrogen....

I agree with u. Good job . Can u help me solve the gen chem question in my previous post? Thanks
 
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