Bromine halohydrin question

[predentgal]

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I don't understand why the product is opticaly inactive if we have 4 different atoms on each carbon and there is no symmetry. Can someone explain? Problem is below. Thank you!!🙂

http://yfrog.com/5852985502p

 

[hausee]

http://en.wikipedia.org/wiki/Meso_compound

 

[Gaussian]

You will make two enantiomers with the same probability of formation; in other words you make a racemic mixture.

 

[Gaussian]

Note that, you start with a cis compound which becomes a threo after anti addition; threo compounds cannot be meso!
Also, there is no plane of symmetry!

 

[hausee]

Note that, you start with a cis compound which becomes a threo after anti addition; threo compounds cannot be meso!
Also, there is no plane of symmetry!

you are right.👍

 

[Alanine]

i dont understand why III is true, i thought you couldnt have a chiral center if there was a double bond.