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- Jul 11, 2009
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I understand that a bulky base will yield the less substituted product (Hoffman) in an elimination reaction. However, Chad mentions that's not always the case -- you can get the Zaitsev product if dealing with a bulky base and secondary halide.
For purposes of the DAT, how should I treat this:
bulky base = always Hoffman, or
bulky base = Zaitsev/Hoffman depending on the bulkiness of halide?
For purposes of the DAT, how should I treat this:
bulky base = always Hoffman, or
bulky base = Zaitsev/Hoffman depending on the bulkiness of halide?