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guys how do you do this:
if sin(2teta)= 2sine[teta]cos[teta] then
(sine 15)(cos 15)= ?
a. 1/4
b. sqroot of 2/4
c. sqroot of 3/4
d. 1
please explain how you got your ans. thanks.
if sin(2teta)= 2sine[teta]cos[teta] then
(sine 15)(cos 15)= ?
a. 1/4
b. sqroot of 2/4
c. sqroot of 3/4
d. 1
please explain how you got your ans. thanks.
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