chain rule question

[dk00]

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h(t)=30(sinπt/6)


please help and explain steps

 

[PRmed]

h(t)=30(sinπt/6)


please help and explain steps

 

[sodiumd]

We have h(t)=30sin(πt/6).
Let u=πt/6
Thus, h(u)=30sin(u).
Chain rule is (dh/dt)=(dh/du)*(du/dt)
dh/du=30cos(u)
du/dt=π/6
(dh/dt)=(dh/du)*(du/dt)=30π/6cos(u)=5πcos(u)
Replacing "u", we have 5πcos(πt/6)

EDIT: Oops. I was too late.

 

[dk00]

thank you guys so much i couldnt figure out why i was getting wrong answer
thanks!!!