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I was wondering as to how I would get the percent composition of O in a hydrate i.e. What is the percent composition of O in C2H6 * 5H2O? I made up the formula I know that this is called a hydrate.
So the way I would go about doing this is:
mass of O/mass of whole hydrate *100
80/110 *100 = 73%
Is this right?
So the way I would go about doing this is:
mass of O/mass of whole hydrate *100
80/110 *100 = 73%
Is this right?