Confuscious say what!

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rdhdds1

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I am seeking some clarification: Destroyer 30 (ochem) I am stuck between B and C (and even though this is my 3rd time going through it) I still do not see how the structure forms. Can anyone help? And yes I know it is not A and D/E are not present do to cropping besides they are incorrect as well. B is the right answer.
 

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Okay Okay I think I figured it out after posting the thread. Sorry. But if anyone would like to clarify for me that would be great. Just to ensure that I do have it.

The bonds flip after the right side fo the figure is raised to make the table right? Then the CHO-C (triple bond) C-CHO is added which makes the other side of the structure including the double bond. Pretty close?
 
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Diels Alder.
So just to clarify but if you add up the electrons you would find there are an extra two (making it b not c)

The way I would do is it simpler, I just say double bond goes to single and triple to double. In this case it is the latter.
good luck on your DAT, know your taking it soon.
 
This is what separates destroyer from the rest, the reaction is a deals-alder and what happens is the diene loses a doubel bond and gives up two electrons to the dieneophile. The other double bond shifts between where the diene was. The dienophile also loses a pi bond and 2 electrons, so it goes from triple to double.
 
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