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deleted647690
In EK1001, I was trying to do a problem that showed a basic inclined plane with a pulley on a box with some tension T. "The plane above is inclined at a 30 degree angle. The coefficient of kinetic friction between the mass and the plane is 0.1. The mass is 100 kg. What is the minimum tension required in the rope so that the mass will accelerate down the plane at 2 m/s^2?"
I used a = Fnet / m
The force of friction and tension and both acting up, while the mgsintheta component is acting downwards.
So 2 m/s^2 = Force of friction + Tension - mgsin theta / m
Force of friction = u * mg cos theta
Force of friction = 86
2 m/s^2 = 86 + T + -500 / 100
T = 614
This was not correct. The correct answer was 213 N. In the key, they set up mgsintheta = u mgcostheata + T + ma. What is this "ma" term? I am confused about what this additional force is that they are adding into the equation. Why does a = fnet/m not work with the way I had it set up?
Thank you
I guess my real question is about how to set up the net forces correctly. I keep messing those up.
I'm not really sure what the "ma" term means in this question. If the box is accelerating downwards, shouldn't "ma" be added to the downward force side?
I used a = Fnet / m
The force of friction and tension and both acting up, while the mgsintheta component is acting downwards.
So 2 m/s^2 = Force of friction + Tension - mgsin theta / m
Force of friction = u * mg cos theta
Force of friction = 86
2 m/s^2 = 86 + T + -500 / 100
T = 614
This was not correct. The correct answer was 213 N. In the key, they set up mgsintheta = u mgcostheata + T + ma. What is this "ma" term? I am confused about what this additional force is that they are adding into the equation. Why does a = fnet/m not work with the way I had it set up?
Thank you
I guess my real question is about how to set up the net forces correctly. I keep messing those up.
I'm not really sure what the "ma" term means in this question. If the box is accelerating downwards, shouldn't "ma" be added to the downward force side?
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