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hey guys i am having trouble understanding the answer to this question... here goes
A radioactive decay series begins with Uranium-238 and proceeds by emission of the following sequences of particles: alpha, beta, beta, alpha, alpha, and alpha. what is the atomic number of the final isotope formed at the end of the series?
Topscore says the answer is 84. Is that right? I thought that alpha changes the atomic number by -4 and beta changes it by +1 which would add up to -6 right? am i being stupid...please help thanks guys
kyle 🙂
A radioactive decay series begins with Uranium-238 and proceeds by emission of the following sequences of particles: alpha, beta, beta, alpha, alpha, and alpha. what is the atomic number of the final isotope formed at the end of the series?
Topscore says the answer is 84. Is that right? I thought that alpha changes the atomic number by -4 and beta changes it by +1 which would add up to -6 right? am i being stupid...please help thanks guys
kyle 🙂