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destroyer roadmap question

whoaaitzkyle

go bears!
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Sep 29, 2005
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  1. Dental Student
    My question is about the reaction of ethyl benzene with K2Cr2O7. There is a carbon missing int the products?!?!? The result is benzoic acid. Is this an error?

    K2Cr2O7 is a really strong oxidizing agent. It will change that carbon chain into a carboxylic acid. Benzoic acid is the correct answer...good eye though!
     
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    bigasianpianist

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    Jun 16, 2008
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    1. Pre-Dental
      Well the potassium dichromate oxidizes any alkyl group on the aromatic ring, and it leaves it with only a carboxylic acid. The rest of the alkyl becomes another molecule in the solution. I'd do the mechanism but all you have to know is that the strong oxidizers (i.e. the K2Cr2O7, KMnO4 and etc) will remove the rest of the alkyl and leave a COOH in its place. Hope this helps
       

      topdent1

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      Aug 6, 2007
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      1. Pre-Dental
        Well the potassium dichromate oxidizes any alkyl group on the aromatic ring, and it leaves it with only a carboxylic acid. The rest of the alkyl becomes another molecule in the solution. I'd do the mechanism but all you have to know is that the strong oxidizers (i.e. the K2Cr2O7, KMnO4 and etc) will remove the rest of the alkyl and leave a COOH in its place. Hope this helps

        So even if it was a 10 carbon chain, it would screw the 9 carbons and convert that one into an acid? Thanks!
         
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