Eas with 2 ACTIVATING rings

[510586]

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I know that was reactions with 2 rings only add to one side like this oneone , but what if they are both activating instead of one act one deact

 

[cacajuate]

The more activating wins

 

[DrNutmeg]

Is B the answer?

Ketone = meta
Amine = ortho/para

process of elimination...

 

[510586]

Is B the answer?

Ketone = meta
Amine = ortho/para

process of elimination...

This was an activating and deactivating.

The more activating wins

Thanks

 

[DrNutmeg]

what was the answer?

 

[510586]

what was the answer?

Oh sorry. Yea B was the answer. The explanation said one ring would be activating and one deactivating so i asked if both were deactivating. Also if there are 2 electron withdrawing groups on one benzene ring, the stronger EWG would dictate correct? Like cooh would direct not Cl for example on one benzene ring.

 

[DrNutmeg]

oh my b, I didn't read your question; I just tried to answer the question in the picture lol.

 

[Typical Average Student]

Stronger activator always wins, regardless of how weak it is. Ex. CH3 will win over NO3 despite NO3 being a strong EWG. Br will win over NO3.

 

[Incis0r]

Why can't the answer be A or E?
The C=O is EWG....given. It's a meta director. Given. Shouldn't it brominate on the meta position on the ring closest to the C=O? This isn't a FC reaction where deactivated rings can't get more substituents...

And the Br on the ring closest to the NH director should be on O and P positions.

 

[DrNutmeg]

Why can't the answer be A or E?
The C=O is EWG....given. It's a meta director. Given. Shouldn't it brominate on the meta position on the ring closest to the C=O? This isn't a FC reaction where deactivated rings can't get more substituents...

And the Br on the ring closest to the NH director should be on O and P positions.

You are only adding 1 equivalent of Br. A and E have too many Br groups added.

 

[Incis0r]

You are only adding 1 equivalent of Br. A and E have too many Br groups added.

Oh okay. If it said excess, then would E be the correct answer?

 

[DrNutmeg]

I don't think so. After you add 1 Bromine to the right group, it makes the positions meta to the Bromine less reactive because Bromine (although a deactivating group) is an ortho/para director.

 

[Incis0r]

I don't think so. After you add 1 Bromine to the right group, it makes the positions meta to the Bromine less reactive because Bromine (although a deactivating group) is an ortho/para director.

Bromine is a deactivating group and O/P director, and it's true that adding it to a ring deactivates the ring more, but the NH still controls where future substituents will go since it is a stronger activator...right?

 

[DrNutmeg]

I'd go for choice A if there were xs Br2 and Fe2Br3. But, your logic makes sense to me; I could be totally off-track with the 1 equivalent thing.