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- Jul 19, 2011
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for question 23:
CO + 1/2 O2 --> CO2 H= -283
At very high temp, rxn 1 will most likely:
answer is nonspontaneous and exothermic.
I understand why it is nonspontaneous. But wouldn't it go in reverse direction if the temp is high b/c enthalpy is negative so it is like adding temp to the products so...but the answer doesn't consider that. It just looks at forward reaction, which I understand. But normally, if I'm right the reaction would go in reverse correct? I guess b/c this equation doesn't have the double arrow, I should have not though about the reverse reaction but only the forward even with high temp it would go forward only!!!1
CO + 1/2 O2 --> CO2 H= -283
At very high temp, rxn 1 will most likely:
answer is nonspontaneous and exothermic.
I understand why it is nonspontaneous. But wouldn't it go in reverse direction if the temp is high b/c enthalpy is negative so it is like adding temp to the products so...but the answer doesn't consider that. It just looks at forward reaction, which I understand. But normally, if I'm right the reaction would go in reverse correct? I guess b/c this equation doesn't have the double arrow, I should have not though about the reverse reaction but only the forward even with high temp it would go forward only!!!1