Electrochemistry Cell question

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bchang57

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Why is this correct?
Zn(s)|Zn2+||Cu2+|Cu(s)

and not this?
Cu(s)|Cu2+||Zn2+|Zn(s)

for a Daniell Cell?


does anyone know why can't Zinc be reduced instead of Cu? Achiever doesn't really say
 
you have to look at E knot (standard) value for both copper and zinc from the activity series. smaller number gets oxidized..i think
 
Look at the reduction potentials Eknot. The one with the highest number will be the one that gets reduced because its the most spontaneous.

Remember dG=-nFE and the more negative dG is the more spontaneous it is.

So if one value is -.9 V and the other is -.8V then the element being reduced with the -.8 V will be the one you leave being reduced and you change the other element with -.9V to being oxidized. When you analyze the dG value -> .8 < .9 and .8 is closer to being negative and therefore more spontaneous.

Hope this helps..
 
Why is this correct?
Zn(s)|Zn2+||Cu2+|Cu(s)

and not this?
Cu(s)|Cu2+||Zn2+|Zn(s)

for a Daniell Cell?


does anyone know why can't Zinc be reduced instead of Cu? Achiever doesn't really say


Daniell Cell is a type of Galvanic/Voltaic Cell which is spontaneous so Ecell > 0

Reduction potentials:
Zn2+ + 2&#8202;e&#8722; &#8594; Zn(s) -0.76V
Cu2+ + 2&#8202;e&#8722; &#8594; Cu(s) +0.34V

For the reaction to have a + Ecell, Zn must be oxidized (+0.76V) and Cu2+ must be reduced (+0.34V). Ecell = reduction potential + oxidation potential = 0.76V + 0.34V = 1.10V


Shorthand Notation for galvanic cell: Anode/oxidation || Cathode/reduction
|| represents the salt bridge


Zn is OXidized at the ANode.
Cu2+ is REDuced at the CAThode.

Zn(s)|Zn2+||Cu2+|Cu(s)


why can't Zinc be reduced instead of Cu?
If Zn2+ is reduced (Note: Zn cannot be reduced ie gain electrons), Cu is oxidized.
Ecell = reduction potential + oxidation potential = -0.76V + -0.34V = -1.10V
If Ecell < 0 then this reactions is not spontaneous and it cannot be a Daniell Cell/ Galvanic/Voltaic Cell.
 
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