- Joined
- Jan 10, 2012
- Messages
- 327
- Reaction score
- 68
Which of the following will increase the value of the equilibrium constant for the following reaction? CaCO3(s) ↔ CaO(s) + CO2(g) ΔH = 178kJ
Increasing the temperature
Decreasing the temperature
Adding CaCO3
Removing CO2
I put decreasing the temp cause the enthalpy was positive and therefore the reaction is endothermic, so deccreasing temp would induce more products to be produced and increasing the rate constants.
Is my logic wrong because it only increases Q not Keq and for almost every reaction increasing temp increases KE and more collision so reaction becomes faster?
Increasing the temperature
Decreasing the temperature
Adding CaCO3
Removing CO2
I put decreasing the temp cause the enthalpy was positive and therefore the reaction is endothermic, so deccreasing temp would induce more products to be produced and increasing the rate constants.
Is my logic wrong because it only increases Q not Keq and for almost every reaction increasing temp increases KE and more collision so reaction becomes faster?
