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Fairly simple genetics question...

Discussion in 'DAT Discussions' started by Cofo, Aug 3, 2011.

  1. Cofo

    Cofo Super Cool Member
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    Suppose an animal has a gene for coat color that is sex-linked (X-linkage) and incompletely dominant, and in which females with an AA genotype have a black coat color; aa individuals have a yellow color; and those with Aa have a marble coloration. If a marble female was crossed with a yellow male, then each of the following might result under normal Mendelian conditions EXCEPT one. Which one is the EXCEPTION?

    Black male
    Black female
    Yellow male
    Yellow female
    Marble female

    I am almost certain the answer is Black female. Can anyone evoke me to have full certitude please?
     
  2. jmukid

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    I think its black females also. A cross of Aa with aa will produce 50% Aa and 50% aa. No AA is produced which is the genotype for black females.
     
  3. HannibalLecter

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