Four Random Questions...

[fannian]

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1) How many molecules of glucose does cellular respiration produce per mol of glucose?

2) A lesion to the hypothalamic-hypophyseal portal systm would not effect production of

a) LH
b) growth hormone
c) ACTH
d) TSH
e) Norepinephrine

3) What volume of water would be needed to dilute 50ml of a 3M HCl solution to 1M?

a) 25ml
b) 50ml
c) 75ml
d) 100ml
e) 150ml

4) What volume of 0.5M NaOH is needed to neutralize 25 mL of 2M H2SO4?

a) 50ml
b) 75ml
c) 100ml
d) 150ml
e) 200ml

By the way, for those of you that took the Kaplan Course, what method did they teach for the RC part of the test? What method did you use, and how effective was it?

Thanks

 

[I AM SARA]

1) How many molecules of glucose does cellular respiration produce per mol of glucose?

2) A lesion to the hypothalamic-hypophyseal portal systm would not effect production of

a) LH
b) growth hormone
c) ACTH
d) TSH
e) Norepinephrine

3) What volume of water would be needed to dilute 50ml of a 3M HCl solution to 1M?

a) 25ml
b) 50ml
c) 75ml
d) 100ml
e) 150ml

4) What volume of 0.5M NaOH is needed to neutralize 25 mL of 2M H2SO4?

a) 50ml
b) 75ml
c) 100ml
d) 150ml
e) 200ml

By the way, for those of you that took the Kaplan Course, what method did they teach for the RC part of the test? What method did you use, and how effective was it?

Thanks

you should buy the course.

 

[fannian]

you should buy the course.

I heard it's not worth it, the only good things are the practice tests, right?

 

[HITMAN]

1. You're a little confused, respiration breaks down 2 molecules of pyruvate produced from glycolysis and produces 30 ATP. Net 6 ATP are also produced in glycolysis (4 from NADH) for a total of 36/glucose molecule. Keep in mind, respiration begins after glycolysis.

2. E- Norepi is produced by the adrenal medulla, the others are produced by the anterior pituitary.

3. E (.05L)(3M)=(x)(1M)

4. E (.025L)(2M)(2 H+/mol)=(.5M)(x)

 

[fannian]

1. You're a little confused, respiration breaks down 2 molecules of pyruvate produced from glycolysis and produces 30 ATP. Net 6 ATP are also produced in glycolysis (4 from NADH) for a total of 36/glucose molecule. Keep in mind, respiration begins after glycolysis.

2. E- Norepi is produced by the adrenal medulla, the others are produced by the anterior pituitary.

3. E (.05L)(3M)=(x)(1M)

4. E (.025L)(2M)(2 H+/mol)=(.5M)(x)

I don't have the answers on me, but I know at least, that 3 might be wrong, as well as 1:

1. They are asking about Cellular Respiration, so I would subtract 4 from 36, which will yield 32, right? I'm still confused? Why four and not two?

3. Wouldn't the answer be D. Becasue wouldn't you ADD 100ml of water to dilute it to a total of 150ml? Your answer results in a final volume of 50ml + 150ml = 200ml. I may be wrong, but I'm still a little confused!

HELP PLEASE!

But thanks at least for your response!

 

[dat_student]

1. They are asking about Cellular Respiration, so I would subtract 4 from 36, which will yield 32, right? I'm still confused? Why four and not two?

Cellular respiration (just the oxy part):
Eukaryotes: 32 ATPs
Aerobic prokaryotes: 34 ATps

Total ATP = 36 ATPs

Those are the numbers Kaplan and many books and tests give.
Some scientists didn't know how to calculate ATPs. They said 36 ATPs and now it's impossible to convince many people 36 is not the right number.
In reality, you don't get 36 ATPs
You get 30 ATPs (eukaryotes), and 32 ATPs (Prokaryotes)
Unfortunately, 99.9% of books over-estimate the amount of energy a cell can produce.

3. Wouldn't the answer be D. Becasue wouldn't you ADD 100ml of water to dilute it to a total of 150ml? Your answer results in a final volume of 50ml + 150ml = 200ml. I may be wrong, but I'm still a little confused!

It's 100 ml

here is the proof:
.05 L * 3M = 0.15 moles

0.15 moles / .15 L= 1 M
(we we wanted the solution to have Molarity = 1 M)

 

[fannian]

Cellular respiration (just the oxy part):
Eukaryotes: 32 ATPs
Aerobic prokaryotes: 34 ATps

Total ATP = 36 ATPs

Those are the numbers Kaplan and many books and tests give.
Some scientists didn't know how to calculate ATPs. They said 36 ATPs and now it's impossible to convince many people 36 is not the right number.
In reality, you don't get 36 ATPs
You get 30 ATPs (eukaryotes), and 32 ATPs (Prokaryotes)




It's 100 ml

here is the proof:
.05 L * 3M = 0.15 moles

0.15 moles / .15 L= 1 M
(we we wanted the solution to have Molarity = 1 M)

your good

 

[dat_student]

your good

Here is one of the problems with 36 ATPs:

For every NADH that is oxidized to NAD+ three large electron transport proteins pump about 10 protons across the inner mitochondrial membrane, into the intermembrane space. Since NADH is responsible for the pumping of 10 protons, each molecule of NADH provides the energy to produce approximately 2.5 ATP molecules. (i.e. 10 / 4 = 2.5 ATPs). Plus, only 1.5 ATPs are made as a result of the reoxidation of FADH2 (6 / 4 = 1.5 ATPs). Unfortunately, most books don't know how to correctly calculate the number of ATPs. Most likely, ADA also believes the right answer is 36 ATPs.

 

[fannian]

Here is one of the problems with 36 ATPs:

For every NADH that is oxidized to NAD+ three large electron transport proteins pump about 10 protons across the inner mitochondrial membrane, into the intermembrane space. Since NADH is responsible for the pumping of 10 protons, each molecule of NADH provides the energy to produce approximately 2.5 ATP molecules. (i.e. 10 / 4 = 2.5 ATPs). Plus, only 1.5 ATPs are made as a result of the reoxidation of FADH2 (6 / 4 = 1.5 ATPs). Unfortunately, most books don't know how to correctly calculate the number of ATPs. Most likely, ADA also believes the right answer is 36 ATPs.

NERD ALERT! jk

I thought NADH produces 3, and FADH2 produces 2. What, are you doing research on the electrochemical behavior of biochemical species involving the aerobic machinary of eukaryotics mitochondira and the associated proteins involved in cellular respiration? If you are, then let me know when the paper is out.

Bottom line, what does ADA recognize as the correct answer - probably what kaplan recognize - so I'll go with them!

Thanks anyways!

 

[dat_student]

What, are you doing research on the electrochemical behavior of biochemical species involving the aerobic machinary of eukaryotics mitochondira and the associated proteins involved in cellular respiration?

No, I 1st learned about it from Dr. Daniel J. Pallin, M.D. 😉 He is a smarty. 😉

 

[puncho]

It's 100 ml

here is the proof:
.05 L * 3M = 0.15 moles

0.15 moles / .15 L= 1 M
(we we wanted the solution to have Molarity = 1 M)

I'm getting a bit stressed out here and can't think straight.. 😕

Kaplan, it says for dilution, MiVi = MfVf and they give the example: How many mL of a 5.5 M NaOH solution must be used to prepare 300 mL of a 1.2 M NaOH solution?

Solution: 5.5 M x V1 = 1.2 M x 0.3 L
V1 = 65mL

So I guess my question is: When do you know to add the initial quantity? I should know this but I'm having a hard time thinking right now 😡

 

[HITMAN]

My falt, I was thinking neutralize instead of dilute. It's 100 ml for #3.

By the way puncho, to answer your question, dilution is when you add H2O to the given solution, whereas the Kaplan question you cited refers to preparing a separate solution.

 

[fannian]

I'm getting a bit stressed out here and can't think straight.. 😕

Kaplan, it says for dilution, MiVi = MfVf and they give the example: How many mL of a 5.5 M NaOH solution must be used to prepare 300 mL of a 1.2 M NaOH solution?

Solution: 5.5 M x V1 = 1.2 M x 0.3 L
V1 = 65mL

So I guess my question is: When do you know to add the initial quantity? I should know this but I'm having a hard time thinking right now 😡

Since no one is help you out, I'll calm your nerves. Read the question, but slower. Your question just says 'How many mL of a 5.5M NaOH solution' is needed; NOTHING ABOUT HOW MUCH OF SOMETHING NEEDS TO BE ADDED!

The answer is 65 mL of the NaOH is needed. But if the question asked how much water needed to be added, then the answer would be 300 - 65.

Is this right guys? I'm a little confused now too, but I think I've explained it correctly.

 

[BenignDMD]

I heard it's not worth it, the only good things are the practice tests, right?

Yea, don't take it...waste of 1000 bucks...I have a friend who works there, so I just got copies of the tests. The tests are really simple too.

 

[BenignDMD]

Since no one is help you out, I'll calm your nerves. Read the question, but slower. Your question just says 'How many mL of a 5.5M NaOH solution' is needed; NOTHING ABOUT HOW MUCH OF SOMETHING NEEDS TO BE ADDED!

The answer is 65 mL of the NaOH is needed. But if the question asked how much water needed to be added, then the answer would be 300 - 65.

Is this right guys? I'm a little confused now too, but I think I've explained it correctly.

Yea thats right....if you were given how many mL and M of a starting solution, and then given the final M, then you would have to subtract the final mL from the beginning one