Free Radical

[busdent]

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can you explain me why B is the answer? Thanks



I thought it is Anti-markovnikov only in the presense of peroxides..but this question doesn't state that. Achiever shows B as the correct answer. Their reasoning is that it is anti-mark. addition where bromine radical selectively attacks the less substituted carbon to produce the most stable tertiary radical.

 

[GRAD]

When you have hv, it makes it a free radical, and with free radicals and rings, they add at the least substituted place, so wherever that it, add it =) good luck.

 

[artmed12]

Achiever is correct here...

Br2 /hv = markovnikov
HBR/ peroxides = anti-markovnikov
HBR/hv = anti-markovnikov

the difference here is HBr vs. Br2

HBr in hv or peroxides will be anti-markovnikov