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friction problem

Discussion in 'MCAT Study Question Q&A' started by FRANK1985, Nov 17, 2010.

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  1. FRANK1985

    FRANK1985

    14
    0
    May 27, 2010
    Hey guys, help needed, here goes

    A meteor with a mass = 1Kg moving at 20km/s collides with jupiter's atmosphere. the meteor penetrates 100 km into the atmosphere and dsintegrates. What is the average force on the meteor once it enters Jupiter's atmosphere (ignore gravity)?

    a) 2*10^3 N
    b) 4*10^3 N
    c) 8*10^3 N
    d) 2*10^5 N

    thank you
     
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  3. shffl

    shffl

    130
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    Sep 20, 2010
  4. FRANK1985

    FRANK1985

    14
    0
    May 27, 2010
    that's correct, But i don't get it

    1/2mv^2= F*d
    1/2 * 1 * (20)^2 = F * 100km

    200 = F* 100km
    F= 200/100
    F= 2N

    what am I doing wrong????
     
  5. ModernAlchemist

    ModernAlchemist Transform and Transcend 7+ Year Member

    1,269
    15
    Jan 20, 2008
    Limbo
    Convert Km to m in both the velocity and the displacement.
     
  6. FRANK1985

    FRANK1985

    14
    0
    May 27, 2010
    DUH!!!! I AM SO RETARDED! thank u so much
     
  7. ModernAlchemist

    ModernAlchemist Transform and Transcend 7+ Year Member

    1,269
    15
    Jan 20, 2008
    Limbo
    Don't worry about it haha. That has happened to me about 1 million times.
     
  8. panda2queen

    panda2queen

    1
    0
    Jun 1, 2012
    hey I know this was posted a while back, but I am hoping someone can clarify this problem a little for me. I thought that you would use the equation Fdcos(theta) and cos of 0 is just one so then I thought this was set to equal the change in kinetic energy plus the change in potential energy so it would be F*d = delta K + delta U....how come above you just did F*d = delta K...where did the change of potential energy go?

    thanks!
     
  9. TcDroid4med

    TcDroid4med 5+ Year Member

    30
    14
    May 15, 2011
    the question says to ignore gravitational force ;)
     

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