Funny Question
Started by dat_student
seoul said:
No, How can one have 3 M H+ and 1 M [CO3 ]2- and get 446000000000000000000 M solution????!!!!!!!!
1 M is also wrong.
Hint: "funny question"
seoul said:
I'd like to give everybody a chance to think about it. I'll post something [at some point in the future].
Just going to toss out a guess: 4 M.
Where's the answer? 😀
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Comet208 said:He is still figuring it out
There is nothing to figure out
OK, OK, I'm dumb. Someone want to explain this to me? 😕
seriously ... what's so "funny" about this question? Seems like a typical chemistry question.
I'd say that the answer doesn't exist. My reasoning is that all chemistry is fake. It's a hoax that a bunch of science and math nerds came up with. It's all complete crap.
We have 3 M H+ and 1 M [CO3]2- in a solution. What is the molarity of the solution?
H2CO3 -> H+ + HCO3- -> H+ + [CO3]2-
all we gotta do is find molarity of H and CO3 then add them up.
It's that simple.
I think it's very funny, because I would laugh so bad if this shows up on DAT, since this is piece of cake.
H2CO3 -> H+ + HCO3- -> H+ + [CO3]2-
all we gotta do is find molarity of H and CO3 then add them up.
It's that simple.
I think it's very funny, because I would laugh so bad if this shows up on DAT, since this is piece of cake.
joonkimdds said:
No. Wrong answer [don't laugh too much] 😉
Is it even possible to have two different molarities in one solution? This question is really weird. I'm not going to post anything else because it's just frustrating me now. 😡
Flipper405 said:
It's possible. You can assume that 2H+ combine with 1 [CO3]2-. In that case, you'll be left with 1 M H+ and 1 M H2CO3 which has a low dissociation constant.
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dat_student said:
This is totally just a guess but:
H+ is a strong acid, and (CO3)2- is a very strong base. In solution, equilibrium will shift towards the formation of the weaker conj. acid and base which would be HCO-, but since H+ is in excess H2CO3 will form. The formation of H2CO3 will use up two moles of H+, there will still be 1 mol of H+ left and 1 mol of the newly formed product H2CO3. If they are already in solution together as a 1L soln then the molarity would be 2M, because 2 moles of solute in 1L of solution.
mccarth2 said:
No, if that were the case the question wouldn't be funny, bb in 1-2 hr(s)
dat_student said:
We have 3 M H+ and 1 M [CO3]2- in a solution. What is the molarity of the solution?
H2CO3 -> H+ + HCO3- -> H+ + [CO3]2-
first of all....there are couple of errors in this problem
the equation has two arrows , it should only have 1 arrow. I've never seen an equation with two arrows. that's just wrong.
2nd of all.. u said 3M, what does M mean?
dat_student said:
H2CO3 is going to dissociate very fast to H2O and CO2. This acid is not stable at all.
bump
