- Joined
- May 7, 2004
- Messages
- 173
- Reaction score
- 0
What is the molality of 85% phosphoric acid, H3PO4, if the density of the solution is 1.70 g/ml?
A. 1000 * (1.70/1) * (100.0 / 15.0) * (1.70/1) * (85.0 / 100.0) * (1/98) m
B. 1000 * (1/1.70) * (100.0 / 15.0) * (1.70/1) * (85.0 / 100.0) * (1/98) m
C. 1000 * (1/1.70) * (100.0 / 15.0) * (1/1.70) * (85.0 / 100.0) * (1/98) m
D. 1000 * (1/1.70) * (15.0 / 100.0) * (1.70/1) * (85.0 / 100.0) * (1/98) m
E. 1000 * (1/1.70) * (100.0 / 15.0) * (1.70/1) * (100.0 / 85.0) * (1/98) m
the correct answer is B according to DAT achiever. Im having trouble setting this thing up.
A. 1000 * (1.70/1) * (100.0 / 15.0) * (1.70/1) * (85.0 / 100.0) * (1/98) m
B. 1000 * (1/1.70) * (100.0 / 15.0) * (1.70/1) * (85.0 / 100.0) * (1/98) m
C. 1000 * (1/1.70) * (100.0 / 15.0) * (1/1.70) * (85.0 / 100.0) * (1/98) m
D. 1000 * (1/1.70) * (15.0 / 100.0) * (1.70/1) * (85.0 / 100.0) * (1/98) m
E. 1000 * (1/1.70) * (100.0 / 15.0) * (1.70/1) * (100.0 / 85.0) * (1/98) m
the correct answer is B according to DAT achiever. Im having trouble setting this thing up.