Gen Chem Help

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.
How many grams of Al2(SO4)3 are needed to make 87.5 g of 0.3 m Al2(SO4)3 solution?? I am stuck....

I would say 10.26g.
If the answer is correct, or if anyone agrees, i will explain why.

if I am wrong, plz don't make fun of me, I am in a bad mood today😛 jk...
 
i got 8.975 too.

.3mol/1000g x 87.5 g = .02625mol

.02625mol x 342g/1mol = 8.975g
 
yeah, u guys r right.
I was too lazy, i converted 87.5g into 0.0875kg and I assumed that it's same as 0.1kg becuz I am practicing how to calculate fast without using calculator. so yes, 0.875 is more accurate answer.
 
Top