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What is the molarity of a 70.0% concentrated nitric acid, HNO3, if the density of solution is 1.42 g/ml?
A. 1000 * (1.42/1) * (70.0 / 100.0) * (1/63) M
B. 1000 * (1/1.42) * (70.0 / 100.0) * (1/63) M
C. 1000 * (1.42/1) * (100.0 / 70.0) * (1/63) M
D. (1/1.42) * (70.0 / 100.0) * (1/63) / 1000 M
E. (1.42/1) * (70.0 / 100.0) * (1/63) / 1000 M
Does A make sense? Thanks
A. 1000 * (1.42/1) * (70.0 / 100.0) * (1/63) M
B. 1000 * (1/1.42) * (70.0 / 100.0) * (1/63) M
C. 1000 * (1.42/1) * (100.0 / 70.0) * (1/63) M
D. (1/1.42) * (70.0 / 100.0) * (1/63) / 1000 M
E. (1.42/1) * (70.0 / 100.0) * (1/63) / 1000 M
Does A make sense? Thanks