gen chem problem

[chyuk84]

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The value of K​

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c for the reaction below is 2.0.
C(s) + CO2(g) 2 CO(g)
What is the concentration of CO at equilibrium if the
CO2 concentration is 0.50 M?
A. 2.0 M
B. 1.5 M
C. 1.41 M
D. 1.0 M​

E. 0.50 M

The answewr is D which is 1.0 M. I thought it would be 2M becuase there are 2 CO. Am I not supposed to multiply 1 M by 2 because there are 2 moles of CO?

 

[Danny289]

The value of K​

​

c for the reaction below is 2.0.
C(s) + CO2(g) 2 CO(g)
What is the concentration of CO at equilibrium if the
CO2 concentration is 0.50 M?
A. 2.0 M
B. 1.5 M
C. 1.41 M
D. 1.0 M​

E. 0.50 M

The answewr is D which is 1.0 M. I thought it would be 2M becuase there are 2 CO. Am I not supposed to multiply 1 M by 2 because there are 2 moles of CO?

K= ([co]^2)/ [co2] ===========> 2 X.5 = [co]^2 ====> [co]=1

 

[harrygt]

The value of K​

c for the reaction below is 2.0.

C(s) + CO2(g) 2 CO(g)
What is the concentration of CO at equilibrium if the
CO2 concentration is 0.50 M?
A. 2.0 M
B. 1.5 M
C. 1.41 M
D. 1.0 M​

E. 0.50 M

The answewr is D which is 1.0 M. I thought it would be 2M becuase there are 2 CO. Am I not supposed to multiply 1 M by 2 because there are 2 moles of CO?

Kc = [CO]^2/[CO2]

2 = x^2 / 0.5 ---> x = 1 M

Boy, you are making the same mistake of that Ksp problem. Just solve for [CO] in this equation. Look at the Kc expression. plug in the [CO2] and solve for [CO].

 

[Danny289]

Kc = [CO]^2/[CO2]

2 = x^2 / 0.5 ---> x = 1 M

Boy, you are making the same mistake of that Ksp problem. Just solve for [CO] in this equation. Look at the Kc expression. plug in the [CO2] and solve for [CO].

hi bro, noway comparing this one to Ksp lol

 

[TexasDent]

Kc=[Prod]/[React]....And you only use gases and aqueous liquids.

This is the complete way to do it. But the first reply is the easier way by just substituting in [CO] for (2x).

Using this equation you plug the values given into it. Since you have 2CO then you will plug in (2x)^2 for the product concentration and 0.5 for the Reactant concentration.

2=(4x^2)/0.5.... (4x^2)=1....... x^2=(1/4)..... x=0.5

The concentration of CO is 2x (from above). So plug in 0.5 into x.

2(0.5)= 1M CO