M
marypredds
Advertisement - Members don't see this ad
If I needed to make 2.00L of 1.50M HCL from a 12.0M HCL stock solution, I would need .250L of the 12.0M HCL to do so (I've already calculated V1.)
How would I actually make the diluted solution? I would first take .250L of 12.0M HCL and combine it with 1.75L of water making a 2.00L solution?
How would I actually make the diluted solution? I would first take .250L of 12.0M HCL and combine it with 1.75L of water making a 2.00L solution?
