H NMR Help

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Psa

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According to topscore this molecule will only have 2 singlets. Can someone explain why the 4 H's in the aromatic ring are considered a singlet? Shouldn't it be a doublet since each H in the ring has at least 1 neighboring hydrogen?

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There are only 2 groups: the H's on the aromatic and the hydrogens on the carbon attached the oxygen.

It's considered a singlet because they are all equivalent to each other and are part of the same group. Equivalent hydrogens don't alter the singlet/doublet thingie.
 
There are only 2 groups: the H's on the aromatic and the hydrogens on the carbon attached the oxygen.

It's considered a singlet because they are all equivalent to each other and are part of the same group. Equivalent hydrogens don't alter the singlet/doublet thingie.

I get that there are 2 groups due the symmetry of the molecule. But I still dont get why the the neighboring H's in the ring don't count.
 
I'm pretty sure it's because equivalent hydrogens don't affect the multiplicity of the peak. Don't wanna give you the wrong answer though.

According to my notes on Chads: neighbors = nonequivalent hydrogens less than 3 bonds away.
 
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I'm pretty sure it's because equivalent hydrogens don't affect the multiplicity of the peak. Don't wanna give you the wrong answer though.

I think i get it. You're saying that the whole benzene ring is considered a single group, just like the 3 H's in the methyl are considered one. I'm just confused because I thought that whenever the H's were on separate carbons, they always got the n+1 amount of peaks as the neighboring H's.
 
for the benzene ring keep in mind that those double bonds are not fixed i.e. there is a delocalization of electrons and therefore you only see 1 H. i think thats why
 
for the benzene ring keep in mind that those double bonds are not fixed i.e. there is a delocalization of electrons and therefore you only see 1 H. i think thats why

I definitely remember chad mentioning that now! I need to re-watch some stuff b4 my test
 
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