Ok be I am pretty sure the EK book is wrong on this one.
this is question 982
there are 2 convergent lens place 28 cm appart. First lens f=24cm second lens f=9cm. a object is placed 6 cm to the left of first lense so it looks like this
object---6cm---L1----28cm-----L2
Anyways so I work on the first lens first
1/f=1/di+1/do
1/24=1/6+1/do
do=-8
so it looks like this
Image (upright) --2cm--object-6cm---L1----28cm-----L2
the image is upright and and virtual and to the left
so the new do would be 8+28=36 and...
1/9=1/36+1/di
di=12
Image (upright) --2cm--object-6cm---L1----28cm---L2---12cm---image (inverted!)
Since the image is on the other side it is inverted
maginfication of the l1=-(-8/6)=4/3 l2=-(12/36)=-1/3 which means the total magnification -4/9 however all the answers are positive WTF....
this is question 982
there are 2 convergent lens place 28 cm appart. First lens f=24cm second lens f=9cm. a object is placed 6 cm to the left of first lense so it looks like this
object---6cm---L1----28cm-----L2
Anyways so I work on the first lens first
1/f=1/di+1/do
1/24=1/6+1/do
do=-8
so it looks like this
Image (upright) --2cm--object-6cm---L1----28cm-----L2
the image is upright and and virtual and to the left
so the new do would be 8+28=36 and...
1/9=1/36+1/di
di=12
Image (upright) --2cm--object-6cm---L1----28cm---L2---12cm---image (inverted!)
Since the image is on the other side it is inverted
maginfication of the l1=-(-8/6)=4/3 l2=-(12/36)=-1/3 which means the total magnification -4/9 however all the answers are positive WTF....
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