Help with electrochemistry

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September24

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This is problem 957 in EK 1001 chemistry

Consider the electrochemical cell that utilizes lithium and zinc


Li-+e-=Li E0= -3.05V
Zn(2+)+2e-=Zn E0= -0.76V

What is the standard voltage for this cell.


I understand that E0cell=Ecathode-Eanode

Here, zinc is a better oxidizing agent so it will be reduced at cathode. Therefore lithium will be oxidized at anode.

Oxidation potential for lithium is 3.05V while the reduction potential for zinc is -0.76.

If Ecell=Ecathode-Eanode
Ecell= -0.76-(+3.05)

Ecell= -3.81


However, the answer according to EK is 2.29V. I feel like I grossly have a concept messed up here.
 
This is problem 957 in EK 1001 chemistry

Consider the electrochemical cell that utilizes lithium and zinc


Li-+e-=Li E0= -3.05V
Zn(2+)+2e-=Zn E0= -0.76V

What is the standard voltage for this cell.


I understand that E0cell=Ecathode-Eanode

Here, zinc is a better oxidizing agent so it will be reduced at cathode. Therefore lithium will be oxidized at anode.

Oxidation potential for lithium is 3.05V while the reduction potential for zinc is -0.76.

If Ecell=Ecathode-Eanode
Ecell= -0.76-(+3.05)

Ecell= -3.81


However, the answer according to EK is 2.29V. I feel like I grossly have a concept messed up here.

Nope, you're exactly right, just be careful with the signs while doing cell potential calculations. It's better to remember the equation as:

Ecell = Ereduction + Eoxidation

Since zinc is reduced, and lithium is oxidized, you have to remember to flip the sign in the Ereduction of lithium to get Eoxidation of lithium

Ecell = -0.76 - (-3.05)
Ecell = 2.29V
 
Ohhhhh. Okay. So since I already flipped the sign for lithium's potential, I can just add the two potentials?

I assume the cathode-anode equation already incorporates the flipped signs? Basically, if I recognize that lithium is the anode and the potential must become reversed, I can just add the two? Sorry if its getting confusing.
 
Yep, that's right. Just remember when reading reduction potential tables to flip the signs for the opposite (oxidation) reaction, then it's just a simple matter of adding the two values. That's why I like to remember Ecell = Ereduction + Eoxidation. It makes it easier to keep track of signs.
 
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