HWeq..Q simple

[utdent20]

Advertisement - Members don't see this ad

I know this is easy but i can't get the numbers to work..
A population of rabbits is in HWeq, with 9% of population homozygous recessive for the albino trait. The % of the population that is heterozygous for the ablino trait is ??
21 % is the answer.. can someone show me the steps..
so q=9% thus P=91% so 2 pq= 2*9*91??
I have been studying too long i think its time for a break.. Thanks for who answers it..

 

[nixon13]

so your homozygous recessive is your P^2, homozygous dominant is Q^2 and your heterozygotes is 2pq right? So you know that your P^2 is 9% or .09. So if you take the square root of that, you ge .3 which is also your P value. Now if you have your P value, then you know your Q value from P + Q = 1. So your Q turns out to be .7. Now you know your heterozygote percentage which is 2(.3)(.7)= .42. Now its asking you for just the albino recessive trait which is half of that or .21. hope this helps! Good luck.

 

[utdent20]

I get it.. Thanks. But i am still wondering why we have to half it? Beacuse it did not mention recessive, its just asking for heterozygous for the trait..

 

[tranv117]

yeah it doesnt make sense to me either. If youre specifically looking for the number of heterozygotes, it seems like it should be 42%. I don't get why itd be 21%. Also if you add up all the numbers p^2 + 2pq + q^2 = 1. If we said the percent of heterozygotes were 21 percent and not 42 percent, it doesnt add up to 1.

Someone care to explain this?