Hydraulic lift question. HELP

[dorjiako]

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A hydraulic lift has a cylinder with a radius of 5cm. What should be the radius of the other cylinder so that the force applied to the first cylinder is multiplied by a factor of 10.

 

[inaccensa]

My attempt

P1=P2
F1/A1=F2/A2
10F1/piR1^2=F1/piR2^2
10/25=1/r^2
R^2=25/10?

 

[raffster2]

F1/A1=F2/A2. Since you're talking about radius, you need to make sure that you square the radius because the equation is in terms of area. So F1/A1=F2/A2 --> Let's say F1=1N, F2=10N. 1N/5^2cm=10N/x^2. Solve for X, and you will get x^2=250, so x=sqrt(250) which is approximately 15.8 cm.

 

[dorjiako]

I' m good now.

 

[inaccensa]

A hydraulic lift has a cylinder with a radius of 5cm. What should be the radius of the other cylinder so that the force applied to the first cylinder is multiplied by a factor of 10.

didnt they mean to multiply the F1 by 10😕

 

[indianjatt]

didnt they mean to multiply the F1 by 10😕

They did, but the mistake you made was that you said the force is 10x on the same piston, but they wanted a force to be 10x on the other piston so there would be some mechanical advantage. Otherwise, your work is correct.

 

[inaccensa]

hmm 🙁

 

[raffster2]

hmm 🙁

They didn't mean to multiply the force by 10, they mean to ask what radius is required on the second piston so that the force pushed on the first piston is multiplied by 10.

 

[inaccensa]

They didn't mean to multiply the force by 10, they mean to ask what radius is required on the second piston so that the force pushed on the first piston is multiplied by 10.

Makes sense now, thanks