Make sure you can do basic C-13 NMR questions, where you can differentiate between unique carbons to know how many peaks there will be.
For example:
ClH2C-CH2-CH2-CH2-ClH2C
1,5-dichloro-pentane
You would see 3 unique peaks as noted by the following coloring:
ClH2C-CH2-CH2-CH2-ClH2C
carbons 1,5 are equivalent = 1 separate peak
carbons 2,4 are equivalent = 1 separate peak
carbon 3 is equivalent = 1 separate peak