Kaplan General chem question please explain

[ManzRDH]

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Given: Zn(s) + 2 HCl (aq) -----> ZnCl2 (s) + H2 (g)

At std temp and pressure, what vol of hydrogen will be produced when 6.5 g of Zn is dissolved in HCl

a- .012L
b- .024
c- .12L
d- 1.22 L
e- 2.24L

 

[vertical bite]

start out with PV=nRT

V=nrt/P

go from there.


Vertical bite rules !

 

[vertical bite]

Did that help?


Hint. DETERMINE WHAT THE MOLES ARE and you are 92% there.

 

[luder98]

start out with PV=nRT

V=nrt/P

go from there.


Vertical bite rules !

Mole of H2 = Mole of Zn = 6.5/65 = 0.1

At std temp and pressure, each mole of an ideal gas occupies 22.4 L, therefore the volume would be 0.1*22.4 = 2.24 L

 

[vertical bite]

Mole of H2 = Mole of Zn = 6.5/65 = 0.1

At std temp and pressure, each mole of an ideal gas occupies 22.4 L, therefore the volume would be 0.1*22.4 = 2.24 L

great job WILL DURANT boy !