ManzRDH

Dinene RDH, BA
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Given: Zn(s) + 2 HCl (aq) -----> ZnCl2 (s) + H2 (g)

At std temp and pressure, what vol of hydrogen will be produced when 6.5 g of Zn is dissolved in HCl

a- .012L
b- .024
c- .12L
d- 1.22 L
e- 2.24L
 

vertical bite

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start out with PV=nRT

V=nrt/P

go from there.


Vertical bite rules !
 

vertical bite

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Did that help?


Hint. DETERMINE WHAT THE MOLES ARE and you are 92% there.
 

luder98

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vertical bite said:
start out with PV=nRT

V=nrt/P

go from there.


Vertical bite rules !
Mole of H2 = Mole of Zn = 6.5/65 = 0.1

At std temp and pressure, each mole of an ideal gas occupies 22.4 L, therefore the volume would be 0.1*22.4 = 2.24 L
 

vertical bite

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luder98 said:
Mole of H2 = Mole of Zn = 6.5/65 = 0.1

At std temp and pressure, each mole of an ideal gas occupies 22.4 L, therefore the volume would be 0.1*22.4 = 2.24 L



great job WILL DURANT boy !

:laugh: :laugh: :laugh: