Kinetics dr collins

Started by thesituation559
Get help with your application

Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.

Browse articles Compare schools My application plan Read Interview Feedback
Practice for interviews Ask an Advisor
Sort by date Sort by votes
thesituation559 said:
I am having trouble on problems 16-1 and 16-2. If someone could explain those two I would really appreciate it.
Click to expand...

16-1) X + [OH]^Y ---> who cares
Rate = k[OH]^Y [X]
X doesn't matter, they tell you they double the OH concentration and the rate goes from .002 to .008 so it increases fourfold or 4times. You are trying to find Y. So, 2[OH]^Y = 4 so Y = 2

16-2) Since tripling the concentration of A does not change the overall rate it is zeroth order and since doubling the concentration of B doubles the rate it is first order. Therefore rate = k^1 or just , A is not included because it is zeroth order which is just 1, [A]^0 = 1

If you don't understand this still then you need to watch some videos or check out wiki.
 
Upvote 0 Downvote
frankdahtank said:
16-1) X + [OH]^Y ---> who cares
Rate = k[OH]^Y [X]
X doesn't matter, they tell you they double the OH concentration and the rate goes from .002 to .008 so it increases fourfold or 4times. You are trying to find Y. So, 2[OH]^Y = 4 so Y = 2

16-2) Since tripling the concentration of A does not change the overall rate it is zeroth order and since doubling the concentration of B doubles the rate it is first order. Therefore rate = k^1 or just , A is not included because it is zeroth order which is just 1, [A]^0 = 1

If you don't understand this still then you need to watch some videos or check out wiki.
Click to expand...


I understand 16-1, but I'm still a little off on 16-2. So in this case if was still doubled but it tripled the rate it would be second order then?
 
Upvote 0 Downvote
thesituation559 said:
I understand 16-1, but I'm still a little off on 16-2. So in this case if was still doubled but it tripled the rate it would be second order then?
Click to expand...


How do you get that? Rate (change in rate is usually double or zero or quad) = [change in concentration (usually a whole multiple for the PCAT like doubled or tripled or quadrupled] ^x

so if B was doubled and the rate tripled then it would be 3 = 2^x
x= the order
 
Upvote 0 Downvote
You must log in or register to reply here.