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Another question for ya'll! It is good practice 🙂
In aamc chem self assessment #91, "The addition of excess Ca2+ to a solution containing Ca2+ and CO3-2 ions causes CaCO3 to precipitate because:
A: Ksp for CaCO3 would increase due to the increase of Ca2+.
B: Ksp for CaCO3 would decrease due to the increase of Ca2+.
C: The reactivity quotient Q would be lower than the Ksp.
D: The reactivity quotient Q would be higher than the Ksp.
Immediately, A and B could be eliminated since Ksp cannot be changed (it is a constant).
I selected D because the reaction quotient (products over reactants) would decrease because of the increase of Ca2+ ions (reactants). This would shift the reaction towards more product (CaCO3), causing it to precipitate more.
The answer is C because "When CaCO3 is in solution, the following takes place: CaCO3 --> Ca2+ + CO3-2 and Ksp=[Ca][CO3]. When excess Ca is added, CaCO3 precipitates due to le chatliers principle. [CO3] is therefore decreased and Ksp is maintained.
I dont understand the reasoning. I understand that adding Ca increases CaCo3 due to le chatliers, and also decreases CO3 because more of it precipitates, but how does the reaction quotient become lower than the Ksp?
In aamc chem self assessment #91, "The addition of excess Ca2+ to a solution containing Ca2+ and CO3-2 ions causes CaCO3 to precipitate because:
A: Ksp for CaCO3 would increase due to the increase of Ca2+.
B: Ksp for CaCO3 would decrease due to the increase of Ca2+.
C: The reactivity quotient Q would be lower than the Ksp.
D: The reactivity quotient Q would be higher than the Ksp.
Immediately, A and B could be eliminated since Ksp cannot be changed (it is a constant).
I selected D because the reaction quotient (products over reactants) would decrease because of the increase of Ca2+ ions (reactants). This would shift the reaction towards more product (CaCO3), causing it to precipitate more.
The answer is C because "When CaCO3 is in solution, the following takes place: CaCO3 --> Ca2+ + CO3-2 and Ksp=[Ca][CO3]. When excess Ca is added, CaCO3 precipitates due to le chatliers principle. [CO3] is therefore decreased and Ksp is maintained.
I dont understand the reasoning. I understand that adding Ca increases CaCo3 due to le chatliers, and also decreases CO3 because more of it precipitates, but how does the reaction quotient become lower than the Ksp?