Ksp, Keq, Kw, Rate, Q !?!?!?!?

[pandalove89]

Okay so whenever I do chemistry problems pertaining these values I always get confused of how to setup the problem


In my mind I always just do: K = [Products]/[Reactants]

However sometimes, only the products show up while the reactants aren't even part of the equation.

Also, when we do fill in the products part, say there are 2 moles of one of the products, do we always do this? --> so if there are 2 moles of x....2x^2
Because sometimes the 2 in front of the x is missing, sometimes the it becomes 4x^2, and sometimes it just stays at 2x^2.



Please help!

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[Dental2000]

Keq = [Products]/[Reactants]

Q is used to identify if the reaction is favouring products or reactant
its the same equation as Keq

K<Q = reaction favours reactants
K>Q = reaction favours products
K=Q means reaction is at equilibrium

Ksp is similiar to Keq excpet the reactant in a Ksp equation is always solid hence whose concentration(its assumed as 1) is never taken into the Ksp eq

As for your last question, Im not sure what your asking about the '2 moles' bit. If you can give me a sample question thats confusing you about the concentrations part then i can try and explain it to you better

Hope this helps....

 

[Dental2000]

Oh and Kw = 1 x 10^-14= Ka x Kb

Ka = acid dissociation constant
Kb= base dissociation constant

 

[rmm30]

Okay so whenever I do chemistry problems pertaining these values I always get confused of how to setup the problem


In my mind I always just do: K = [Products]/[Reactants]

However sometimes, only the products show up while the reactants aren't even part of the equation.

Also, when we do fill in the products part, say there are 2 moles of one of the products, do we always do this? --> so if there are 2 moles of x....2x^2
Because sometimes the 2 in front of the x is missing, sometimes the it becomes 4x^2, and sometimes it just stays at 2x^2.



Please help!

Thats asking a whole lot. More than can be covered in a response. You should get Chad's videos. He covers all of your questions in full over the course of about 75 minutes of lecture. Trust SDN community and Chad on this one.