I was hoping someone could help me make sense of this -- I'm following all of it until the explanation talks about cubing 5.5.. why is 5.5 cubed?
What is the minimum number of moles of Be(OH)2(s) must be added to one liter of water in order to create a saturated solution if the Ksp of Be(OH)2(s) is 6.92 x 10-22?
Ksp = [Be2+][OH-]2. So the expresion for molar solubility and Ksp becomes Ksp = (x)(2x)2 = 4x3. The value 6.92 x 10-22 can be approximated to ~10-21, so the cube root is about 10-7 (eliminate choices B and D). 6.92/4 is about 7/4 or 1.75. Cubing 5.5 gives a number greater than 125 and less than 216 (5 and 6 cubed, respectively), making choice C the best answer
What is the minimum number of moles of Be(OH)2(s) must be added to one liter of water in order to create a saturated solution if the Ksp of Be(OH)2(s) is 6.92 x 10-22?
Ksp = [Be2+][OH-]2. So the expresion for molar solubility and Ksp becomes Ksp = (x)(2x)2 = 4x3. The value 6.92 x 10-22 can be approximated to ~10-21, so the cube root is about 10-7 (eliminate choices B and D). 6.92/4 is about 7/4 or 1.75. Cubing 5.5 gives a number greater than 125 and less than 216 (5 and 6 cubed, respectively), making choice C the best answer