S spoog74 Full Member 10+ Year Member Joined Jan 31, 2011 Messages 423 Reaction score 0 Nov 19, 2012 #1 Members don't see this ad. can someone show me a quick and easy way to do this? if a = log7B^7 then what is the value of 7^a? Answer is b^7 Thanks !
Members don't see this ad. can someone show me a quick and easy way to do this? if a = log7B^7 then what is the value of 7^a? Answer is b^7 Thanks !
P PointEstimate Full Member 10+ Year Member Joined Aug 5, 2012 Messages 430 Reaction score 90 Nov 19, 2012 #2 That's one of the logarithm identities: http://en.wikipedia.org/wiki/List_of_logarithmic_identities Upvote 0 Downvote
aqz Full Member 10+ Year Member Joined Jan 27, 2011 Messages 741 Reaction score 327 Nov 19, 2012 #3 It's just how you perform log functions, e.g. the definition of log. x = log(base y)z is defined as y to the power of x = z so log7b^7 = a is 7^a = b^7 Upvote 0 Downvote
It's just how you perform log functions, e.g. the definition of log. x = log(base y)z is defined as y to the power of x = z so log7b^7 = a is 7^a = b^7