Math

[Awuah29]

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For the following statement to be true which of the variables can not be zero? 24x2(y-z)[(9+b)]a = 13.
A. x

B. y

C. z

D. a

E. b

anyone can explain?

 

[JMJRDH1]

It looks to me like "a" cannot be zero.

When you follow PEMDAS for the order of operations, the last operation would be the multiplication of the number * "a", and if "a" were zero, the expression would be equal to zero, which is certainly not 13!

Hope this helps! Math whizzes please correct me if I am wrong.

 

[Lonely Sol]

For the following statement to be true which of the variables can not be zero? 24x2(y-z)[(9+b)]a = 13.
A. x

B. y

C. z

D. a

E. b

anyone can explain?

Well, I think this problem is wrong, because there are two right answers, it could be either x or a.

 

[Drill2Fill]

I would go with answer choice D. Is the "x" a multiplication sign or variable?

 

[Streetwolf]

x or a. Get a better study guide or look when you type 🙂

 

[marscole]

I will take "a" as my answer. However, "x" could also be a right answer. Therefore, "x" and "a" cannot be zero.

 

[a3344305]

Personally think "x" and "a" are the answers

 

[Nasem]

Forget order of operation... the whole problem is one big giant multiplication.

If you multipy ANYTHING by zero you get zero. If x or a is zero then your answer is automatically zero.

answer = x and a

 

[iistoogood4u]

Maybe he meant X to be an exponent?
(24x)2(y-z)[(9+b)]a = 13
or 24^x2(y-z)[(9+b)]a = 13
or even (24)x2(y-z)[(9+b)]a = 13
but it doesnt quite make sense looking like his original equation seeing 24x2 when it could have been written 48x(...)