Molarity of solution?

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

khadcheemz

Full Member
7+ Year Member
Advertisement - Members don't see this ad
What is the molarity of a solution of H2SO4 if 100 ml of this solution requires 25 mL of 2 M NaOH for complete neutralization?

Isn't this N1V1=N2V2?

I thought it was 1.0 M but its .25 M
 
(2mol/L of OH-)(25mL of solution) = 0.5mmol of OH = 0.5mmol of H+
(0.5mmolH+) (1mmol H2SO4/2mmolH+) = 0.25mmol H2SO4
0.25mmolH2SO4/100mL = 0.25M of H2SO4 initial.
 
You can do it this way because NaOH is a strong base, so you can assume it dissociates 100%.
H2SO4 is a strong acid you have to assume the it also dissociates 100% twice.
 
Advertisement - Members don't see this ad
Yeah, in the real world you know the second H doesn't dissociate 100% but i guess in terms of the DAT you would have to assume it does.
Oh ok just checking thanks. On a pH problem they could potentially ask it like that right? Then we would treat the second H as not a complete [H+] right?
 
Oh ok just checking thanks. On a pH problem they could potentially ask it like that right? Then we would treat the second H as not a complete [H+] right?
That's a really good question. I think if its a strong acid, you can assume this. If it isn't a strong acid you can't assume this.
If you have a specific question, I think it would be best to ask Dr. Romano.
Also, if they don't give you any pKa's or Ka's, your going to have to assume it dissociates twice.