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A reaction is shown below:
Addition of a peroxide compound to this reaction will give the following product:
The answer key says addition of peroxide will result in anti-Markovnikov addition. However, from what I learned from Chad's videos, I thought peroxides do anti-Markovnikov ONLY with Bromine. Here in the problem, since we are dealing with chlorine with peroxides, shouldn't the addition to the alkene be Markovnikov? So, the result will be the chlorine being attached to the tertiary carbon (with the methyl group). Is the answer key wrong?
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