Neutralization Reactions/Hydrolysis of Salts

[ModusProbandi]

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I don't get neutralization reactions. When we are talking about complete neutralization, lets say you have a weak base and a strong acid. Are we stating that a neutralization reaction would occur if you have equimolar amounts of weak base and strong acid because each H+ ion provided by the acid would be neutralized by each OH- provided by the base or does neutralization mean the theoretical amount of acid + base needed to turn each H+ and OH- into water?

Let's say we had NaOH + HF -> NaF + H2O.

NaF is a basic salt, meaning that some of the F- would technically strip some H+ ions from aqueous solution yielding HF, causing the solution to be basic which would mean there technically wouldn't be a neutralization reaction, since now we would have HF (as well as some OH-, the cause of the basic nature of the salt). So what exactly is a neutralization reaction. Is it just the theoretical amount of acid you have to add to the base to hypothetically neutralize the -OH from the base and the H+ from the acid? 😕

 

[blackandgold1]

From what BR said, or atleast what I understood is, that its basically the theoretical amount you need to add to neutralize the moles present. In titrations even, you add enough base or acid to neutralize the exact number of moles of the counterpart, yet after a complete titration you can still have a basic or acidic solution pH. So technically, you neutralized the acid/base present by adding equal parts, yet the pH is not 7. Neutralization reactions dont mean that the pH will always be 7, because after neutralization, you can still have the conjugate base/acid/whatever left over in excess.

This is what BR said for titrations so im generalizing becuase it makes sense, but I might be wrong

 

[ModusProbandi]

From what BR said, or atleast what I understood is, that its basically the theoretical amount you need to add to neutralize the moles present.

Great thanks!

 

[ridethecliche]

Isn't the deal with having a weak acid/base that it'll serve as a buffer because it doesn't dissociate as readily?