A anonymuz dance! 10+ Year Member 15+ Year Member Joined Jan 17, 2006 Messages 195 Reaction score 0 Jul 18, 2010 #1 Members do not see this ad. 3-ethyl-1,1-dimethyl-4-propylcyclohexane how come you dont name the propyl group 1, ethyl group 2 and the dimethyl's 4? thanks
Members do not see this ad. 3-ethyl-1,1-dimethyl-4-propylcyclohexane how come you dont name the propyl group 1, ethyl group 2 and the dimethyl's 4? thanks
D DQLEUCD Full Member 10+ Year Member Joined Jun 30, 2010 Messages 271 Reaction score 0 Jul 18, 2010 #2 anonymuz said: 3-ethyl-1,1-dimethyl-4-propylcyclohexane how come you dont name the propyl group 1, ethyl group 2 and the dimethyl's 4? thanks Click to expand... You need the lowest combinations of substituants. Lets say you have the option of 1,2,4 or naming it in reverse 2,4,5.. 1,2,4 will always win because you have 1 which trumps 2 and etc.. I believe that's what your asking, correct? Upvote 0 Downvote
anonymuz said: 3-ethyl-1,1-dimethyl-4-propylcyclohexane how come you dont name the propyl group 1, ethyl group 2 and the dimethyl's 4? thanks Click to expand... You need the lowest combinations of substituants. Lets say you have the option of 1,2,4 or naming it in reverse 2,4,5.. 1,2,4 will always win because you have 1 which trumps 2 and etc.. I believe that's what your asking, correct?
Baylor2011 DDS Apprentice 10+ Year Member Joined Sep 10, 2009 Messages 451 Reaction score 0 Jul 18, 2010 #3 Because you need the lowest total number when numbering substituents.. let me explain If you numbered 1 from the methyl groups to 4 w/ propyl.. you have 1 (CH3) + 1(CH3) + 3 (Eth) + 4 (Prop) = 9 If you numbered from 1 being propyl to 4 being methyls you'd have 1 (prop) + 2 (eth) + 4 (CH3) + 4 (CH3) = 11 9 is less than 11, so that numbering is preferred Upvote 0 Downvote
Because you need the lowest total number when numbering substituents.. let me explain If you numbered 1 from the methyl groups to 4 w/ propyl.. you have 1 (CH3) + 1(CH3) + 3 (Eth) + 4 (Prop) = 9 If you numbered from 1 being propyl to 4 being methyls you'd have 1 (prop) + 2 (eth) + 4 (CH3) + 4 (CH3) = 11 9 is less than 11, so that numbering is preferred