A passage in the test shows a table of a list of elements going through radioactive decay. These decays result in a new nucleus.
One of the nucleus formed is "californium". Californium is also used as a reactant for radioactive decay.
Then, one of the questions asks:
"What can be concluded about the stability of californium..?"
I chose:
A. It is less stable than most; thus it is used as a reactant element in the synthesis of other actinides.
HOWEVER, the right answer is:
B. It is more stable than most; thus it is used as a reactant element in the synthesis of other actinides.
The explanation states that "The more stable the nucleus, the more easily it can be used as a reactant for radioactive decay".
This seems counterintuitive. I was under the impression that the nucleus of a radioisotope is unstable. In an attempt to reach a more stable arrangement of its protons and neutrons, the nucleus will spontaneously decompose to form a different nucleus. Thus, if the nucleus is stable it would NOT go under radioactive decay.. 😕
Any help would be highly appreciated! 🙂
Thanks!
One of the nucleus formed is "californium". Californium is also used as a reactant for radioactive decay.
Then, one of the questions asks:
"What can be concluded about the stability of californium..?"
I chose:
A. It is less stable than most; thus it is used as a reactant element in the synthesis of other actinides.
HOWEVER, the right answer is:
B. It is more stable than most; thus it is used as a reactant element in the synthesis of other actinides.
The explanation states that "The more stable the nucleus, the more easily it can be used as a reactant for radioactive decay".
This seems counterintuitive. I was under the impression that the nucleus of a radioisotope is unstable. In an attempt to reach a more stable arrangement of its protons and neutrons, the nucleus will spontaneously decompose to form a different nucleus. Thus, if the nucleus is stable it would NOT go under radioactive decay.. 😕
Any help would be highly appreciated! 🙂
Thanks!