o chem question

[ToothFairy423]

---

Members do not see this ad.

problem on topscore i dont get

cyclo octane that is conjugated (has 4 double bonds)

wouldnt this be considered anti aromatic? topscore doesnt seem to think so, so im am confused.

can anyone help

 

[DrTacoElf]

http://www.tamug.tamu.edu/mars/chem227/aromatics.htm


According to huckel's rule to be a aromatic a molecule must be conjugated and contain 4n + 2 pi electrons. Cyclooctane has 8 pi electrons and it is conjugated so it is antiaromatic (4n, n=2) pi electrons as opposed to aromatic 4n+2 pi electrons. Compounds that are non-conjugated are non-aromatic.

n must always be an integer.

 

[ToothFairy423]

http://www.tamug.tamu.edu/mars/chem227/aromatics.htm


According to huckel's rule to be a aromatic a molecule must be conjugated and contain 4n + 2 pi electrons. Cyclooctane has 8 pi electrons and it is conjugated so it is antiaromatic (4n, n=2) pi electrons as opposed to aromatic 4n+2 pi electrons. Compounds that are non-conjugated are non-aromatic.

n must always be an integer.

so it is safe to assume that topscore is wrong"???

 

[joy2dmd]

problem on topscore i dont get

cyclo octane that is conjugated (has 4 double bonds)

wouldnt this be considered anti aromatic? topscore doesnt seem to think so, so im am confused.

can anyone help

I'm pretty sure this question #98 on test 1 has been rewritten, that is that's what the scholarware site says http://www.scholarware.com/DATFix07.x.htm

But if it the question I'm thinking of, answer C is cyclooctatetraene, sure it has 8 pi electons, which, according to Huckle should make the molecule antiaromatic. But the molecule itself is not planar (it forms kind of a cube shape) and therefore the pi electrons do not interact. This molecule is stabe, and behaves as a normal alkane. My text classifies it as non-aromatic which is consistent with its chemical properties. It's not antiaromatic and why their website has this question updated.

So to answer your question, I believe the question has been updated.

 

[ToothFairy423]

I'm pretty sure this question #98 on test 1 has been rewritten, that is that's what the scholarware site says http://www.scholarware.com/DATFix07.x.htm

But if it the question I'm thinking of, answer C is cyclooctatetraene, sure it has 8 pi electons, which, according to Huckle should make the molecule antiaromatic. But the molecule itself is not planar (it forms kind of a cube shape) and therefore the pi electrons do not interact. This molecule is stabe, and behaves as a normal alkane. My text classifies it as non-aromatic which is consistent with its chemical properties. It's not antiaromatic and why their website has this question updated.

So to answer your question, I believe the question has been updated.

wow thanks alot you have been so insightful

how do you know that it is a cube shape?" is this just something you memorized... i hope its stuff like this, that i dont know, and have no way of knowing, that doesnt mess up my score!

 

[joy2dmd]

wow thanks alot you have been so insightful

how do you know that it is a cube shape?" is this just something you memorized... i hope its stuff like this, that i dont know, and have no way of knowing, that doesnt mess up my score!

No, I just looked up why answer C was not antiaromatic. It was an exception so I was curious. Topscore was great, like everyone says.. so when I missed a question, I looked it up. I think i was puzzled or asked scholarware. i think they sent me the solution to this one.