O-chem question

[busdent]

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In the reaction CH4 Cl2, hv =


A. CH3CL
B. CH2CL2
C. CHCL3
D. CCL4
E. All of the above.

I thought it would just be answer A but kaplan shows E as the answer. Is that right? If so, can somebody explain the answer? Thanks

 

[Manyak222]

Remember, this is a radical driven reaction and those can go on and on and.. u get the point. Cl can form all kinds of products, it is "promiscuous" in radical form, unlike bromine, and will add to almost anything. Thus, all of those are possible products, ending only when a termination step occurs (less likely)

In the reaction CH4 Cl2, hv =


A. CH3CL
B. CH2CL2
C. CHCL3
D. CCL4
E. All of the above.

I thought it would just be answer A but kaplan shows E as the answer. Is that right? If so, can somebody explain the answer? Thanks