TX Hopeful

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ManzRDH said:
which has the highest energy and why?

2p

3s

3d

4s

3p
Remember your quantum numbers...
n=the principal quantum number and represents the energy level
l=the azimithal quantum number where s=0, p=1, d=2, and f=3.

2p --> n=2, l=1. 2+1=3
3s --> n=3, l=0. 3+0=3
3d --> n=3, l=2. 3+2=5
4s --> n=4, l=0. 4+0=4
3p --> n=3, l=1. 3+1=4

Therefore, 3d has the highest energy. You can also figure this out by drawing an orbital energy diagram that is too difficult to format on here but can be found in several textbooks or DAT review books.
 

Divineimpetus

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3D,

Deals with how electrons fill their orbitals. I would just memorize it but you can look at it in a mathematical way in the (n + L) rule

Where n is the number, example: (2p: n = 2) (3s: n = 3) (4f: n = 4)

Where L is the letter, example: s = 0, p = 1, d = 2, f = 3

............................


So,

2p = (2 + 1) = 3

3s = (3 + 0) = 3

3d = (3 + 2) = 5 <---- highest number = highest energy

4s = (4 + 0) = 4

3p = (3 + 1) = 4
....

Thus the highest energy orbital is 3D.

If you have the Kaplan blue book (3rd edition), page 199 explains this well.
ManzRDH said:
which has the highest energy and why?

2p

3s

3d

4s

3p
 
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M

ManzRDH

Dinene RDH, BA
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Divineimpetus said:
3D,

Deals with how electrons fill their orbitals. I would just memorize it but you can look at it in a mathematical way in the (n + L) rule

Where n is the number, example: (2p: n = 2) (3s: n = 3) (4f: n = 4)

Where L is the letter, example: s = 0, p = 1, d = 2, f = 3

............................


So,

2p = (2 + 1) = 3

3s = (3 + 0) = 3

3d = (3 + 2) = 5 <---- highest number = highest energy

4s = (4 + 0) = 4

3p = (3 + 1) = 4
....

Thus the highest energy orbital is 3D.

If you have the Kaplan blue book (3rd edition), page 199 explains this well.
Thanks for you help-I have the red kaplan book- i will look into is some more