orgo q

Started by nixon13
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NaOC2H5 is a strong base! I'm not sure if it is considered a bad leaving group, but I don't think it's a good leaving group!

OC2H5 is similar to OH- but an even worse leaving group because the C2H5 is electron donating (on top of the negative charge on the Oxygen)...OH- is a bad leaving group...
 
NaNH2 is basically NH2, which is basically the strongest base, pKa of like 45 or 50, maybe 60...
 
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NaNH2 is s strong base, check out destroyer ochem road map #5 all the way to the right you have 1,2 dichloro butane...it forms 1-butyne...
 
OC2H5 is similar to OH- but an even worse leaving group because the C2H5 is electron donating (on top of the negative charge on the Oxygen)...OH- is a bad leaving group...

Straight from wikipedia..... (lability is the ability for a functional group to leave)
In room temperature water, the sequence of lability is:
Less lability
amine NH2−
methoxy CH3O−
hydroxyl HO−
carboxylate CH3COO−
F−
water
Cl−
Br−
I−
azide N3−
thiocyanate SCN−
nitro NO2
Greater Lability

NO3− is also weaker than F−.
 
NaNH2 is a very powerful base that can be used in almost all eliminations. It is a stronger base than even acetlyne anion and therefore can be used to alkylate an alkyne. Dunno if it is a stronger base than a grignard?? i wonder??
 
When ever you see NaNH2 realize that an elimination is taking place and will form a multiple bond. See road maps in destroyer.
 
NaNH2 is a very powerful base that can be used in almost all eliminations. It is a stronger base than even acetlyne anion and therefore can be used to alkylate an alkyne. Dunno if it is a stronger base than a grignard?? i wonder??

I doubt its stronger than grignard. An alkane has a pKa of 60, making its conjugate base, the grignard, very very strong.