This isn't from any particular study guide. It's just a concept I was reviewing and wanted to make sure I had correct.
Object H has large mass (heavy).
Object L has small mass (light).
If H was placed on a Hooke's Law spring compressed by distance X and released such that H is projected straight up, the resulting initial velocity would be smaller than that of L in the same situation.
(1/2)kx^2 = (1/2)mv^2 :: solve for v
As a result, the max height for H will be less than L.
(1/2)kx^2 = mgh :: solve for h
or
v = sqrt(2gh) :: solve for h
If both H and L were placed on the spring AT THE SAME TIME and compressed by X, the initial velocities of both objects are the same and H and L will reach the same height.
This make sense and I'm fairly confident it's correct, but I haven't touched Physics in a while. Thanks.
Object H has large mass (heavy).
Object L has small mass (light).
If H was placed on a Hooke's Law spring compressed by distance X and released such that H is projected straight up, the resulting initial velocity would be smaller than that of L in the same situation.
(1/2)kx^2 = (1/2)mv^2 :: solve for v
As a result, the max height for H will be less than L.
(1/2)kx^2 = mgh :: solve for h
or
v = sqrt(2gh) :: solve for h
If both H and L were placed on the spring AT THE SAME TIME and compressed by X, the initial velocities of both objects are the same and H and L will reach the same height.
This make sense and I'm fairly confident it's correct, but I haven't touched Physics in a while. Thanks.