Probability problems

Started by Awuah29
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Awuah29

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Anyone know how to tackle those problems ?
In a certain casino, you are paid winnings if you roll a seven with two die.
What are your chances of rolling a seven in one toss?
1/6
1/3
1/36
3/36
1/2

In a regular deck of fifty-two cards, what is the probability of drawaing a daimond on the first try?
13/26
1/13
1/4
1/26
1/52

What is the probability of rolling double threes in one toss of a nine sided die and a six sided die?
1/36
1/6
1/15
1/27
1/54

thanks guys!
 
What is the probability of six tails out of nine tosses of a fair coin?

p = probability of getting a tails (1/2)
C(x,y) where x = 9 and y = 6.
C(x,y) = x!/[y!*(x-y)!]

The equation to solve this is (just memorize it):

C(x,y)*p^(x)*(1-p)^(x-y)

Plug in the values for x and y and you should get 21/128


Is the any shortcut to solve that probleme above without memorizing this formula? x, and y is just confusing 😀

Any hint?
 
Awuah29 said:
Anyone know how to tackle those problems ?
In a certain casino, you are paid winnings if you roll a seven with two die.
What are your chances of rolling a seven in one toss?
1/6
1/3
1/36
3/36
1/2

There are 6 ways of getting a seven:
die A die B
1 6
2 5
3 4
4 3
5 2
6 1

so, the odds of getting seven is 6/36(6x6) which is 1/6.


Awuah29 said:
In a regular deck of fifty-two cards, what is the probability of drawaing a daimond on the first try?
13/26
1/13
1/4
1/26
1/52

There are 13 diamonds in a deck. 13/52 = 1/4

Awuah29 said:
What is the probability of rolling double threes in one toss of a nine sided die and a six sided die?
1/36
1/6
1/15
1/27
1/54

only 1 three on each die, so 1/6 * 1/9 = 1/36